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•(lhs:rhs:)
kareman edited this page Aug 13, 2020
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3 revisions
@inlinable public func •<Input>(lhs: AndPattern<OneOf<Input>>, rhs: OneOf<Input>) -> OneOf<Input>
@inlinable public func •<P: Pattern>(lhs: Concat<P, AndPattern<OneOf<P.Input>>>, rhs: OneOf<P.Input>) -> Concat<P, OneOf<P.Input>>
@inlinable public func •<Input>(lhs: NotPattern<OneOf<Input>>, rhs: OneOf<Input>) -> OneOf<Input>
@inlinable public func •<P: Pattern>(lhs: Concat<P, NotPattern<OneOf<P.Input>>>, rhs: OneOf<P.Input>) -> Concat<P, OneOf<P.Input>>
First tries the pattern to the left, if that succeeds it tries the pattern to the right.
@inlinable public func •<Left, Right>(lhs: Left, rhs: Right) -> Concat<Left, Right> where Left.Input == Right.Input
First tries the pattern to the left, if that succeeds it tries the pattern to the right.
@inlinable public func •<Right: Pattern>(lhs: Literal<Right.Input>, rhs: Right) -> Concat<Literal<Right.Input>, Right>
First tries the pattern to the left, if that succeeds it tries the pattern to the right.
@inlinable public func •<Left: Pattern>(lhs: Left, rhs: Literal<Left.Input>) -> Concat<Left, Literal<Left.Input>>
First tries the pattern to the left, if that succeeds it tries the pattern to the right.
@inlinable public func •<Input>(lhs: Literal<Input>, rhs: Literal<Input>) -> Concat<Literal<Input>, Literal<Input>>
Generated at 2020-08-23T12:56:49+0000 using swift-doc 1.0.0-beta.3.